posted
My question is, if you have, say 2 crossfire cfa 1000d's, connected with thier bridging module, across a one ohm load, each amp will perform as if seeing only half the one ohm load, correct?
then, if so, this will be kinda messy, but is the below true? --If you have one amp, and it's putting out a +35v signal at a specific point in a wave, across 1 ohm=35amps*35v=1225w. -if you put the bridging module before the second amp, it inverts the signal to put out a -35v signal at the same spot, with the 1ohm load in between the +35 and -35, would have 70v with 70amps going through it, producing around 4900w. But, that is without the voltage drops and other details, so basically, with 2 1000w amps bridged, you would get out about 3K? (by numbers 4K, but not real life) I bet that last part is pretty hard to read, but just wondering if I got the right Idea on that.
posted
There are alot of factor that will affect real world output but in theory you will get 4 times the power by bridging two channels together into the same load. 1 channel @ 1 ohm = 1000watts 2 channels bridged @ 1 ohm = 4000watts But yes your math is correct
Yes, because of the doubled voltage and current, each amplifier produces the same voltage but different current, changing the apparent resistance.. Whoa, bedtime
ShadowStar
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