posted
Well here is my real deal problem. This is something i have been trying to figure out by myself and i think i have found the way. But i am not sure, The question is as follows: LxWXH Divided by 1728 gives you the volume in a box. now my question is... how would i go about finding the volume of a box if it had an angle, lets say about 45 degrees, so my box demintions would be this... L - 35" / W (on the bottom) - 7" / H - 25" / W (on the top) - 2" / and the angle down lets say would be maybe... 15" give or take, im not really sure. the point is, i would like to know how to figure this out. So if i could get some help, it would be greatly appriciated. i know it may seem kind of a silly question for an installer to ask, but i have to start learning encloser design some how ). Thanks for your guys help!
------------------ The one and Only Non-Pierced, Mysterious, and Mr. Gumby himself: Grizzlette....
posted
ok for boxes with angles what you do is take the 2 measurments from the same area, say the width is 7 on top and 15 on the bottom, add those 2 together then divide by 2 then that is you width, do the same for the others if they have 2 different measurements and then multiply and divide by 1728. hope that helps.
------------------ Whitlee/2 dudes AL state record holder 41"-50" trunk/passenger 153.0db
Posts: 906 | From: Taylor, AL | Registered: Mar 2000
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